new script for hiding output on success

this script will take a command line to execute and redirect the
commands stdout and stderr to two files.  if the command does not return
an error code, then the output files are just deleted.  if there is an
error reported, then the two files are sent back to stdout and stderr as
they would normally have been, and an additional error message is sent
to stderr.

diff --git a/scripts/testing/squelch_unless_error.sh b/scripts/testing/squelch_unless_error.sh
new file mode 100644 (file)
index 0000000..b59ca5a
--- /dev/null
+++ b/scripts/testing/squelch_unless_error.sh
@@ -0,0 +1,26 @@
+#!/bin/bash
+
+# redirects standard out and standard error output to temp files and runs all the parameters to this script as a command.
+# if there is no error, then the files are just deleted.
+# if there was an error, then the two output file are sent to standard out and standard error.
+# an additional error message is sent to standard error.
+
+#  echo "squelch args: $(printf -- "[%s] " "${@}")"
+
+newout="$(mktemp /tmp/squelch.out.XXXXXX)"
+newerr="$(mktemp /tmp/squelch.err.XXXXXX)"
+
+eval "${@}" >"$newout" 2>"$newerr"
+retval=$?
+
+if [ $retval != 0 ]; then
+  # there was an error during the execution of the command.
+  cat "$newout"
+  cat "$newerr" >&2
+  echo "An error was returned during execution of: ${@}" >&2
+fi
+
+# clean up.
+\rm "$newout" "$newerr"
+
+